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6. Khalid might have added the variable term 1.2y to both sides of the equation and subsequently subtracted the constant term 6.7 from both sides, thereby isolating the variable term and reaching the equation 1.8=1.2y.
7. To find the number of bottles, subtract the empty pack weight 15/16pounds from the total weight 6 9/16 which leaves 5 10/16 pounds for the water. Next, convert the weight of one bottle 1 1/8 to a fraction with the same denominator, which is 18/16 pounds Finally, divide the total water weight 5 10/16 by the weight per bottle 18/16 which equals 5 bottles.
 
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6. Khalid might have added the variable term 1.2y to both sides of the equation and subsequently subtracted the constant term 6.7 from both sides, thereby isolating the variable term and reaching the equation 1.8=1.2y.
7. To find the number of bottles, subtract the empty pack weight 15/16pounds from the total weight 6 9/16 which leaves 5 10/16 pounds for the water. Next, convert the weight of one bottle 1 1/8 to a fraction with the same denominator, which is 18/16 pounds Finally, divide the total water weight 5 10/16 by the weight per bottle 18/16 which equals 5 bottles.
OMG DANG
 

⋆⭒˖𝕽𝖎𝖗𝖎ꫂ᭪݁⋆⭒˖

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8. To simplify the expression, you first group the constant terms and the variable term. You combine the numerical constants by finding a common denominator, which is six. You convert 1/2 to 3/6 and then subtract 1/6 to get 2/6, which simplifies to 1/3. The final simplified expression combines this constant with the variable term, resulting in 1/3w + 1//3
9.
To show the equations are the same without solving them, Edita can convert the fractions into decimals to demonstrate they are identical.
First, the fraction 4/5 is equivalent to 0.8, and the mixed number 1 3/5 is equivalent to 1.6. By substituting these values into the second equation, it becomes 0.8 (x - 1) = 1.6. Next, by applying the distributive property to that equation, it simplifies to 0.8x - 0.8 = 1.6.
Since this matches the first equation exactly, Edita has proven they must have the same solution.
 
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